moles of NaOH = (Average NaOH concentration) .3474 molesNo. of moles of H2SO4 = 2.3474/2 = 1.1737 moles Concentration of H2SO4 = Number of moles / (volume of diluted acid / 1000) LX 10 mL 10/1000) L = 0.4694 MTrail 3:Volume of diluted acid = 25 mLVolume of NaOH used = 37.67 mLAverage concentration of NaOH = 0.0881 MNo. of moles of NaOH = (Average concentration of NaOH) of moles of H2SO4 = 2.3387/2 = 1.1693 moles Concentration of H2SO4 = Number of moles / (volume of diluted acid / 1000) LX 10 mL 10/1000) L = 0.4677 MTrail 4:Volume of diluted acid = 25 mLVolume of NaOH used = 38.32 mLAverage concentration of NaOH = 0.0881 MNo. of moles of NaOH = (Average concentration of NaOH) of moles of H2SO4 = 2.2990/2 = 1.1495 moles Concentration of H2SO4 = Number of moles / (volume of diluted acid / 1000) LX 10 mL 10/1000) L = 0.4598 MTrail 5: Volume of diluted acid = 25